0=12j^2+11j+2

Solution for 0=12j^2+11j+2 equation:

0=12j^2+11j+2

We move all terms to the left:

0-(12j^2+11j+2)=0

We add all the numbers together, and all the variables

-(12j^2+11j+2)=0

We get rid of parentheses

-12j^2-11j-2=0

a = -12; b = -11; c = -2;
Δ = b2-4ac
Δ = -112-4·(-12)·(-2)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-5}{2*-12}=\frac{6}{-24}
=-1/4
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+5}{2*-12}=\frac{16}{-24}
=-2/3
$